Seneca County has the 19th-highest rate of COVID-19 occurrence out of all Ohio counties, according to the Ohio Department of Health.
New data compiled by the Ohio Department of Health and released Tuesday shows the amount of community spread per county over the past two weeks.
Seneca County, with a population of 55,475, has 93.7 positive cases of the novel coronavirus per 100,000 residents, according to state health officials.
Seneca County’s position on the list is above that of neighboring Sandusky County, Huron County, and Crawford County, which placed at 23, 46, and 77, respectively.
Sandusky County has 91.1 cases per 100,000 residents, Huron County has 61.6 cases per 100,000 residents, and Crawford County has 28.6 cases per 100,000 residents.
Wyandot, Hancock, and Wood counties placed higher on the list than Seneca County, with rankings of 3, 5, and 9, respectively.
Wyandot County has 153.8 cases per 100,000 residents, Hancock County has 144 cases per 100,000 residents, and Wood County has 113.9 cases per 100,000 residents, according to the Ohio Department of Health.
The most recent data available from the Seneca County General Health District shows a total of 172 confirmed and probable cases of COVID-19 in the county as of Monday. 81 of those cases are considered active, while 88 are considered recovered, and three people have died with COVID-19 in Seneca County.
We’ve tried to give schools as much information as possible to help them make decisions on how to move forward. Here, we’ve ranked Ohio’s counties by highest occurrence – this shows what the spread has been like in our counties over the last 2 weeks. pic.twitter.com/YC5pJmoWsp
— Governor Mike DeWine (@GovMikeDeWine) August 4, 2020